Originally Posted by Dude
Unless an additional constraint is assumed that there are no coins valued over a quarter, in which case there's only one solution.
No. Assuming that the coins involved are only quarters, dimes, nickels and/or pennies,

Stella could have four quarters and one dime, and Joan could have five dimes and five pennies,

or

Stella could have three quarters, a dime and a penny, while Joan could have one quarter, a dime, and eight pennies.

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