Originally Posted by Iucounu
Originally Posted by Wren
DD's 2nd grade math is pretty basic and then they come up with this problem solving sheet:

Stella has 5 coins
Joan has 10 coins.
Stella has 2 times as much money as Joan
There are only 4 quarters.


What amount of money does Stella have?
What amount of money does Joan have?
What demonination of coins does each have?

There's no solution, because there are multiple possible configurations of the coins.

Unless an additional constraint is assumed that there are no coins valued over a quarter, in which case there's only one solution. Depending on the rest of the worksheet, this assumption may or may not be valid.