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    Joined: Feb 2012
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    They just changed it this year with the current edition, but 2011 was still a little too late to be having this question in a math textbook for elementary-aged kids who can't remember a time without call waiting and cell phones...

    (Answer options are general probability terms of certain...impossible...likely...unlikely...etc.)

    What is the probability of getting a busy signal while making a long-distance phone call?


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    What is the capital of Alaska?

    Seems straight forward enough but when my DH as a third grader stood by his answer Juneau, my in laws were called in for an after school meeting to discuss his stubbornness. The teacher thought it was Willow.

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    Originally Posted by ec_bb
    (Answer options are general probability terms of certain...impossible...likely...unlikely...etc.)

    What is the probability of getting a busy signal while making a long-distance phone call?

    I am completely confused. Are phone numbers more or less prone to busy signals if you're calling from outside a certain area?

    What number am I calling here? Is it a government agency without a menu-driven system (not that they exist these days, but say, the IRS on April 14)? Or my sister when she's not home? The probability of a busy signal is very different for those two numbers in those two situations. It is not, as far as I'm aware, dependent on how far away I am from the phone I'm calling.

    I am so not overthinking this one.

    I think I would just write "Yes" to this question and move on.

    Last edited by Val; 10/22/12 07:59 PM. Reason: Clarity
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    Ok, a new one already! What a week we are having!

    Bryan has three $60 bills. Which expression shows how much money he has?
    A. 60/3
    B. 60-3
    C. 60+4
    D. 60x4

    ??? First of all, where does Bryan live that he has $60 bills? Apparently, it is a world or dimension in which it is not necessary to actually include the correct answer in the multiple choice options. Sigh, I just told him to write in the correct answer.


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    Whoahhh... that one's a doozy in several ways, yes.

    I think that the answer must be A.

    It's obvious. This is a place with funny money. Why not funny math operations, too?

    wink


    Schrödinger's cat walks into a bar. And doesn't.
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    What the...??

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    And how many kids right on the brink of thinking they understand math have permanently given up that idea after reading this problem. What's the chance a teacher would discuss the flaw to improve kids confidence.

    My favorite bit of advocacy:
    Teacher: "Your child has been correcting me in class."
    My Mom: "Well, were you wrong?"

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    I sort of hate to laugh, but I can't stop cracking up about the three $60 bills. $60 bills! How is this for real?

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    Originally Posted by ec_bb
    Kevin is using wooden rods to make picture frames. The length and width of one picture frame and the length of one wooden rod are shown below:

    (diagram of a rectangle with dimensions of 10 inches and 8 inches marked, and a single wooden rod marked with a length of 48 inches)

    1) What is the perimeter, inches, of the picture frame?
    (straight forward -- no complaints there)

    2) How many wooden rods does Kevin need if he makes 4 picture frames like the one above?

    Well, the only answer they gave credit for was 3 -- perimeter x 4 divided by 48.

    I wonder how many kids did the calculation you explained to arrive at 3, and how many checked to see whether or not you could actually cut 8 10" pieces and 8 8" pieces from 3 48" rods. It turns out you can (if you ignore losses due to the width of your saw blade and sanding... which would require you to use 4 rods in the real world). At least the question authors got that much right.

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    Originally Posted by DAD22
    I wonder how many kids did the calculation you explained to arrive at 3, and how many checked to see whether or not you could actually cut 8 10" pieces and 8 8" pieces from 3 48" rods. It turns out you can (if you ignore losses due to the width of your saw blade and sanding... which would require you to use 4 rods in the real world). At least the question authors got that much right.
    I was curious, and did it too-- 10 10 10 10 8, 10 10 10 10 8, 8 8 8 8 8 8. And I had the same thought about widths of the cuts. laugh


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